string - Lua Parse After Match -

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using lua 5.3 i'm trying parse string looks like.

a=data0 b=data c=data a=data1 b=data c=data a=data2 ...

i want parse 'b=data & c=data' after occurrence of 'a=data1'. know can start doing string.find(examplestring, 'a=data1') give me start/end position , know start parsing b after don't know how long 'data' after that, don't know start parsing 'c'? there anyway can parse next line type of thing? how else should tackle this?

know start parsing b after don't know how long 'data' after that, don't know start parsing 'c'? is there anyway can parse next line type of thing?

yes, can match eol character:

for letter, data in s:gmatch('(%w)=(.-)\n')     print(letter,data) end

.- = 0 or more characters, few possible
\n = eol character
parentheses capture parts of pattern want gmatch return.

you ([^\n]*) means 0 or more character not newline.


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