ajax - Django pagination: "show all" implementation -

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i have page list of objects , 2 buttons: show more , show all. objects loaded ajax, sending itemslistview page number:

class itemslistview(listview):     paginate_by = 2

on initializing page, js variable current_page set 1, , js sends ajax request itemslistview view, gets 2 objects first page , renders them.

when user clicks on show more button, current_page value increments, , js requests objects next page.

now want implement show all button. example,

if have following list of objects: [1, 2, 3, 4, 5, 6, 7, 8, 9], on page load objects 1 , 2 rendered. after user clicks on show more, render objects 3 , 4. after user clicks on show all, render objects 5, 6, 7, 8 , 9.

i changed dynamically paginate_orphans in view:

class itemslistview(listview):     paginate_by = 2     paginate_orphans = 0      def get_paginate_orphans(self):         show_all = json.loads(self.request.get.get('show_all', 'false'))         page_kwarg = self.page_kwarg         page = self.kwargs.get(page_kwarg) or self.request.get.get(page_kwarg) or 1         if show_all:             return self.get_queryset().count() - (int(page) - 1) * 2         return self.paginate_orphans

and worked, wonder if there more elegant approach solve problem.

doesn't elegant @ :d more obvious ... 

def get_queryset(self):     show_all = ...     page = ...     qs = super(itemslistview, self).get_queryset()      if show_all:         return qs[int(page)*self.paginate_by:]     else:         return qs

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