How to get a column value based on criteria like where clause in Hbase shell -

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i new hbase.

i have scenario need pull filename based on status , current date.

so have created 3 columns; filename, status , date in hbase table.

how can filename based on condition status=true , date today?

this query needs executed on hbase shell.

achieving in concise way difficult. here did. hbase shell jruby shell, enables following example.

import org.apache.hadoop.hbase.filter.singlecolumnvaluefilter import org.apache.hadoop.hbase.filter.comparefilter import org.apache.hadoop.hbase.filter.substringcomparator import org.apache.hadoop.hbase.filter.filterlist  filter1 = singlecolumnvaluefilter.new(bytes.tobytes('cf'), bytes.tobytes('qualifier'), comparefilter::compareop.valueof('equal'), substringcomparator.new('valuetosearch')); filter2 = singlecolumnvaluefilter.new(bytes.tobytes('cf'), bytes.tobytes('qualifier2'), comparefilter::compareop.valueof('equal'), substringcomparator.new('valuetosearch2'));  filterlist = filterlist.new([filter1, filter2]);  scan 'table', {filter =>  filterlist}

you import other filters, comparator, java objects etc

i have used substringcomparator testing.
in case should binarycomparator (probably better performance wise well).

refer this question if want read more similar hack.

hope helps.


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