regex - Use sed to match end of line NOT preceded immediately by a certain character -

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i have set of lines followed '\' want print line not containing '\' character @ end of line. note xx# yy# change per file , re-usable, want script print lines match1 '\' end of line.

match1 xx1 xx1 xx1 xx1 \ yy1 yy1 yy1 yy1 \ zz\<1\> zz1 zz1 zz1  xx2 xx2 xx2 xx2 \ ...

output should be:

match1 xx1 xx1 xx1 xx1 \ yy1 yy1 yy1 yy1 \ zz\<1\> zz1 zz1 zz1

my best effort came with:

sed -n '/match1/,/\\/p' file

but not work. or suggestions appreciated.

the following command want:

sed -n '/match1/,/[^\\]$/p' file

using ^ @ start of character class negates match.

following glenn jackman's great comment above solution has little problem. since [^\\] requires @ least 1 character not work if first line not ends \ empty line. let me add solution should preferred one:

sed -n '/match1/,/\(^\|[^\\]\)$/p' file

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